12n^2=-48n

Solution for 12n^2=-48n equation:

12n^2=-48n

We move all terms to the left:

12n^2-(-48n)=0

We get rid of parentheses

12n^2+48n=0

a = 12; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·12·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*12}=\frac{-96}{24}
=-4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*12}=\frac{0}{24}
=0
$